c语言中整数类型的显示

1、

#include <stdio.h>

int main(void)
{
    signed short int num1 = 10;
    unsigned short int num2= 10;
    
    signed int num3 = 10;
    unsigned int num4 = 10;
    
    signed long int num5 = 10;
    unsigned long int num6 = 10;
    
    signed long long int num7 = 10;
    unsigned long long int num8 = 10;
    
    printf("signed short int:  %hd.
", num1);
    printf("unsigned short int:  %hu.

", num2);
    
    printf("signed int:  %d.
", num3);
    printf("unsigned int: %u.

", num4);
    
    printf("signed long int:  %ld.
", num5);
    printf("unsigned long int:  %lu.

", num6);
    
    printf("signed long long int: %lld.
", num7);
    printf("unsigned long long int: %llu.
", num8);
    
    return 0;
}

原文地址:https://www.cnblogs.com/liujiaxin2018/p/15013463.html