总结
1、用桶计数,适合数量不多的场景,比如本题,就是记录(0 sim 9)
2、考查数位分离
#include <bits/stdc++.h>
using namespace std;
const int N = 11;
int a[N];
int main() {
int m, n;
cin >> m >> n;
for (int i = m; i <= n; i++) {
int t = i;
while (t) {
int c = t % 10;
a[c]++;
t /= 10;
}
}
for (int i = 0; i <= 9; i++)cout << a[i] << " ";
return 0;
}