HUAS 1480 虫洞(最短路)

把每个点拆成两个点,分别表示黑洞和白洞,然后按题意模拟加边跑最短路即可。

# include <cstdio>
# include <cstring>
# include <cstdlib>
# include <iostream>
# include <vector>
# include <queue>
# include <stack>
# include <map>
# include <set>
# include <cmath>
# include <algorithm>
using namespace std;
# define lowbit(x) ((x)&(-x))
# define pi 3.1415926535
# define eps 1e-9
# define MOD 1000000007
# define INF 1000000000
# define mem(a,b) memset(a,b,sizeof(a))
# define FOR(i,a,n) for(int i=a; i<=n; ++i)
# define FO(i,a,n) for(int i=a; i<n; ++i)
# define bug puts("H");
# define lch p<<1,l,mid
# define rch p<<1|1,mid+1,r
# define mp make_pair
# define pb push_back
typedef pair<int,int> PII;
typedef vector<int> VI;
# pragma comment(linker, "/STACK:1024000000,1024000000")
typedef long long LL;
int Scan() {
    int res=0, flag=0;
    char ch;
    if((ch=getchar())=='-') flag=1;
    else if(ch>='0'&&ch<='9') res=ch-'0';
    while((ch=getchar())>='0'&&ch<='9')  res=res*10+(ch-'0');
    return flag?-res:res;
}
void Out(int a) {
    if(a<0) {putchar('-'); a=-a;}
    if(a>=10) Out(a/10);
    putchar(a%10+'0');
}
const int N=5005;
//Code begin...


int w[N], mark[N], s[N], dist[N<<1];
struct qnode{
    int v, c;
    qnode(int _v=0, int _c=0):v(_v),c(_c){}
    bool operator <(const qnode &r)const{return c>r.c;}
};
struct Edge{
    int v, cost;
    Edge(int _v=0, int _cost=0):v(_v),cost(_cost){}
};
vector<Edge>E[N<<1];
bool vis[N<<1];
priority_queue<qnode>que;

void Dijkstra(int n, int start){
    mem(vis,0);
    FOR(i,1,n) dist[i]=INF;
    dist[start]=0; que.push(qnode(start,0));
    qnode tmp;
    while (!que.empty()) {
        tmp=que.top(); que.pop();
        int u=tmp.v;
        if (vis[u]) continue;
        vis[u]=true;
        FO(i,0,E[u].size()) {
            int v=E[u][i].v, cost=E[u][i].cost;
            if (!vis[v]&&dist[v]>dist[u]+cost) dist[v]=dist[u]+cost, que.push(qnode(v,dist[v]));
        }
    }
}
void addedge(int u, int v, int w){E[u].pb(Edge(v,w));}
int main ()
{
    int n, m, u, v, cost;
    scanf("%d%d",&n,&m);
    FOR(i,1,n) scanf("%d",mark+i);
    FOR(i,1,n) scanf("%d",w+i);
    FOR(i,1,n) scanf("%d",s+i), addedge(i,n+i,0), addedge(n+i,i,s[i]);
    FOR(i,1,m) {
        scanf("%d%d%d",&u,&v,&cost);
        if (mark[u]==mark[v]) addedge(u,n+v,cost), addedge(n+u,v,cost);
        else {
            int delta=abs(w[u]-w[v]);
            addedge(u,v,max(0,cost-delta)); addedge(n+u,n+v,cost+delta);
        }
    }
    Dijkstra(n<<1,mark[1]?n+1:1);
    printf("%d
",min(dist[n],dist[n<<1]));
    return 0;
}
View Code
原文地址:https://www.cnblogs.com/lishiyao/p/6628980.html