LeetCode-Mini Parser

Given a nested list of integers represented as a string, implement a parser to deserialize it.

Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Note: You may assume that the string is well-formed:

  • String is non-empty.
  • String does not contain white spaces.
  • String contains only digits 0-9, [, - ,, ].

Example 1:

Given s = "324",

You should return a NestedInteger object which contains a single integer 324.

Example 2:

Given s = "[123,[456,[789]]]",

Return a NestedInteger object containing a nested list with 2 elements:

1. An integer containing value 123.
2. A nested list containing two elements:
    i.  An integer containing value 456.
    ii. A nested list with one element:
         a. An integer containing value 789.
 
 
Analysis:
One function to parse a list; one function to parse an integer.
 
Solution:
 1 /**
 2  * // This is the interface that allows for creating nested lists.
 3  * // You should not implement it, or speculate about its implementation
 4  * public interface NestedInteger {
 5  *     // Constructor initializes an empty nested list.
 6  *     public NestedInteger();
 7  *
 8  *     // Constructor initializes a single integer.
 9  *     public NestedInteger(int value);
10  *
11  *     // @return true if this NestedInteger holds a single integer, rather than a nested list.
12  *     public boolean isInteger();
13  *
14  *     // @return the single integer that this NestedInteger holds, if it holds a single integer
15  *     // Return null if this NestedInteger holds a nested list
16  *     public Integer getInteger();
17  *
18  *     // Set this NestedInteger to hold a single integer.
19  *     public void setInteger(int value);
20  *
21  *     // Set this NestedInteger to hold a nested list and adds a nested integer to it.
22  *     public void add(NestedInteger ni);
23  *
24  *     // @return the nested list that this NestedInteger holds, if it holds a nested list
25  *     // Return null if this NestedInteger holds a single integer
26  *     public List<NestedInteger> getList();
27  * }
28  */
29 public class Solution {
30     public NestedInteger deserialize(String s) {
31         if (s.length()==0) return null;
32         
33         NestedInteger res;
34         if (s.charAt(0)=='['){
35             res = new NestedInteger();
36             parseList(s,0,res);
37         } else {
38             res = new NestedInteger(0);
39             parseInt(s,0,res);
40         }
41         
42         return res;
43     }
44     
45     // Parse a list starting from index @cur
46     public int parseList(String s, int cur, NestedInteger res){
47         // list always start with '[', skip it
48         cur++;
49         
50         while (s.charAt(cur)!=']'){
51             if (s.charAt(cur)=='['){
52                 // next element is a list.
53                 NestedInteger next = new NestedInteger();
54                 cur = parseList(s,cur,next);
55                 res.add(next);
56             } else {
57                 NestedInteger next = new NestedInteger(0);
58                 cur = parseInt(s,cur,next);
59                 res.add(next);
60             }
61         }
62         
63         // skip ']'
64         cur++;
65         
66         // skip the following ','
67         if (cur<s.length() && s.charAt(cur) == ',') cur++;
68         
69         return cur;
70     }
71     
72     // Parse an integer typed NestedInteger starting from index @cur
73     public int parseInt(String s, int cur, NestedInteger res){
74         boolean isNegative = false;
75         if (s.charAt(cur) == '-'){
76             isNegative = true;
77             cur++;
78         }
79         
80         int num = 0;
81         while (cur<s.length() && s.charAt(cur) >='0' && s.charAt(cur) <='9'){
82             num = num*10+(s.charAt(cur) - '0');
83             cur++;
84         }
85         if (isNegative){
86             num = -num;
87         }
88         res.setInteger(num);
89         
90         // Skip the following ','
91         if (cur<s.length() && s.charAt(cur) == ',') cur++;
92         
93         return cur;
94     }
95 }
 
原文地址:https://www.cnblogs.com/lishiblog/p/5787717.html