A1058 A+B in Hogwarts (20)(20 分)

A1058 A+B in Hogwarts (20)(20 分)

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10^7^], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

AC代码

#include <stdio.h>
int main() {
    int a[3], b[3], c[3];
    scanf("%d.%d.%d %d.%d.%d", &a[0], &a[1], &a[2], &b[0], &b[1], &b[2]);
    int carry = 0;//进位 
    c[2] = (a[2] + b[2]) % 29;//二号位结果 
    carry = (a[2] + b[2]) / 29;//进位 
    c[1] = (a[1] + b[1] + carry) % 17;//一号位结果(加上进位) 
    carry = (a[1] + b[1] + carry) / 17;//进位 
    c[0] = a[0] + b[0] + carry;//无限制,不必再处理进位了 
    printf("%d.%d.%d", c[0], c[1], c[2]);
    return 0;
}
原文地址:https://www.cnblogs.com/lingr7/p/9393318.html