HDU1026

迷宫题

优先队列,然后输出路径

wa的代码,还没找到错哪里

先存起来把,等哪天心情好再改

#include <bits/stdc++.h>
using namespace std;
const int MAXN=110;
char g[MAXN][MAXN];
int b[MAXN][MAXN];
int n,m;
int dx[4]={0,0,-1,1};
int dy[4]={1,-1,0,0};
bool vis[MAXN][MAXN];
struct node{
    int x,y,c;
    friend bool operator <(node a, node b){
        return a.c > b.c;
    }
};
int a[MAXN][MAXN];
priority_queue<node>que;
void init(){
    for(int i=0;i<n;i++){
        for(int j=0;j<m;j++){
            vis[i][j]=false;
            a[i][j]=-1;
        }
    }
    while(!que.empty())que.pop();
}
int bfs(){
    int sx=0,sy=0,gx=n-1,gy=m-1;
    node aa,tt;
    aa.x=sx;aa.y=sy;aa.c=0;
    init();
    que.push(aa);
    while(!que.empty()){
        aa=que.top();que.pop();
        if(aa.x==gx&&aa.y==gy){
            return aa.c;
        }
        if(vis[aa.x][aa.y])continue;
        vis[aa.x][aa.y]=true;
        for(int i=0;i<4;i++){
            int nx=aa.x+dx[i];
            int ny=aa.y+dy[i];
            if(nx<0||ny<0||nx>=n||ny>=m||vis[nx][ny]||g[nx][ny]=='X')continue;
            tt.x=nx;tt.y=ny;
            if(g[nx][ny]=='.')tt.c=aa.c+1;
            else tt.c=aa.c+g[nx][ny]-'0'+1;
            a[nx][ny]=i;//记录方向
            que.push(tt);
        }
    }
    return -1;
}
int tot;
void find_road(int x,int y){
    if(x==0&&y==0)return ;
    find_road(x-dx[a[x][y]],y-dy[a[x][y]]);
    printf("%ds:(%d,%d)->(%d,%d)
",++tot,x-dx[a[x][y]],y-dy[a[x][y]],x,y);
        for(int i=0;i<b[x][y];i++){
            printf("%ds:FIGHT AT (%d,%d)
",++tot,x,y);
        }
}
int main(){
    while(~scanf("%d%d",&n,&m)){
        for(int i=0;i<n;i++){
            scanf("%s",g[i]);
            for(int j=0;j<m;j++){
                if((g[i][j]>='0')&&(g[i][j]<='9')){
                    b[i][j]=g[i][j]-'0';
                }
                else b[i][j]=0;
            }
        }
        int ans=bfs();
        if(ans==-1)
        printf("God please help our poor hero.
");
        else{
            printf("It takes %d seconds to reach the target position, let me show you the way.
",ans);
            tot=0;
            find_road(n-1,m-1);
        }
        printf("FINISH
");
    }


    return 0;
}
View Code
原文地址:https://www.cnblogs.com/lin1874/p/12203505.html