A1065. A+B and C (64bit) (20)

Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <iostream>
 4 #include <string.h>
 5 #include <string>
 6 #include <math.h>
 7 #include <algorithm>
 8 using namespace std;
 9 
10 
11 int main(){
12   
13    int t,tcase=1;
14    scanf("%d",&t);
15    while(t--)
16    {
17        long long a,b,c;
18        scanf("%lld %lld %lld",&a,&b,&c);
19        long long res=a+b;
20        bool flag;
21        if(a>0&&b>0&&res<0)flag=true;
22        else if(a<0&&b<0&&res>=0)flag=false;
23        else if(res>c)flag=true;
24        else flag=false;
25        if(flag==true)
26        {
27            printf("Case #%d: true
",tcase++);
28        }else
29        {
30            printf("Case #%d: false
",tcase++);
31        }
32    } 
33     return 0;
34 }
原文地址:https://www.cnblogs.com/ligen/p/4298806.html