二叉树的遍历(递归、非递归)

 1 public class BinTree {    
 2     private char date;    
 3     private BinTree lchild;    
 4     private BinTree rchild;    
 5     
 6     public BinTree(char c) {    
 7         date = c;    
 8     }    
 9     
10     // 先序遍历递归     
11     public static void preOrder(BinTree t) {    
12         if (t == null) {    
13             return;    
14         }    
15         System.out.print(t.date);    
16         preOrder(t.lchild);    
17         preOrder(t.rchild);    
18     }    
19     
20     // 中序遍历递归     
21     public static void InOrder(BinTree t) {    
22         if (t == null) {    
23             return;    
24         }    
25         InOrder(t.lchild);    
26         System.out.print(t.date);    
27         InOrder(t.rchild);    
28     }    
29     
30     // 后序遍历递归     
31     public static void PostOrder(BinTree t) {    
32         if (t == null) {    
33             return;    
34         }    
35         PostOrder(t.lchild);    
36         PostOrder(t.rchild);    
37         System.out.print(t.date);    
38     }    
39     
40     // 先序遍历非递归     
41     public static void preOrder2(BinTree t) {    
42         Stack<BinTree> s = new Stack<BinTree>();    
43         while (t != null || !s.empty()) {    
44             while (t != null) {    
45                 System.out.print(t.date);    
46                 s.push(t);    
47                 t = t.lchild;    
48             }    
49             if (!s.empty()) {    
50                 t = s.pop();    
51                 t = t.rchild;    
52             }    
53         }    
54     }    
55     
56     // 中序遍历非递归     
57     public static void InOrder2(BinTree t) {    
58         Stack<BinTree> s = new Stack<BinTree>();    
59         while (t != null || !s.empty()) {    
60             while (t != null) {    
61                 s.push(t);    
62                 t = t.lchild;    
63             }    
64             if (!s.empty()) {    
65                 t = s.pop();    
66                 System.out.print(t.date);    
67                 t = t.rchild;    
68             }    
69         }    
70     }    
71     
72     // 后序遍历非递归     
73     public static void PostOrder2(BinTree t) {    
74         Stack<BinTree> s = new Stack<BinTree>();    
75         Stack<Integer> s2 = new Stack<Integer>();    
76         Integer i = new Integer(1);    
77         while (t != null || !s.empty()) {    
78             while (t != null) {    
79                 s.push(t);    
80                 s2.push(new Integer(0));    
81                 t = t.lchild;    
82             }    
83             while (!s.empty() && s2.peek().equals(i)) {    
84                 s2.pop();    
85                 System.out.print(s.pop().date);    
86             }    
87     
88             if (!s.empty()) {    
89                 s2.pop();    
90                 s2.push(new Integer(1));    
91                 t = s.peek();    
92                 t = t.rchild;    
93             }    
94         }    
95     }    
96     
原文地址:https://www.cnblogs.com/licybupt/p/6223860.html