sqlite查询结果在listview中展示

1、获取db实例

SQLiteDatabase db=dbhelper.getWritableDatabase();

2、Cursord对象获取查询结构

Cursor cursor=db.rawQuery("select * from good where number>3",null);

3、新建SimplecursorAdapter对象

SimpleCursorAdapter cursorAdapter=new SimpleCursorAdapter(this, R.layout.golist_item, cursor, new String[]{"_id","name", "price","number"},new int[]{R.id.textView2,R.id.textView3,R.id.textView4,R.id.textView1},CursorAdapter.FLAG_REGISTER_CONTENT_OBSERVER);

simplecusoradapter的构造方法有6个参数(上下文环境,listview布局文件,游标,列名(new string[]{}),显示内容(new int[]{}),flag设置监听)

4、setadapter(cursorAdapter);

Over!

原文地址:https://www.cnblogs.com/librasun/p/5591713.html