lintcode-60-搜索插入位置

60-搜索插入位置

给定一个排序数组和一个目标值,如果在数组中找到目标值则返回索引。如果没有,返回到它将会被按顺序插入的位置。
你可以假设在数组中无重复元素。

样例

[1,3,5,6],5 → 2
[1,3,5,6],2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6],0 → 0

挑战

O(log(n)) time

标签

数组 排序数组 二分法

思路

采用二分查找

code

class Solution {
    /** 
     * param A : an integer sorted array
     * param target :  an integer to be inserted
     * return : an integer
     */
public:
    int searchInsert(vector<int> &A, int target) {
        // write your code here
        int low = 0, high = A.size()-1, size = A.size(), mid = (low+high)/2;
        if(size <= 0) {
            return 0;
        }
        while(low <= high) {
            if(A[mid] == target) {
                return mid;
            }
            else if(A[mid] > target) {
                high = mid - 1;
                mid = (low+high)/2;
            }
            else {
                low = mid + 1;
                mid = (low+high)/2;
            }
        }

        if(A[mid] > target) {
            return mid-1>0 ? mid-1: 0;
        }
        else if(A[mid] < target) {
            return mid+1;
        }
    }
};
原文地址:https://www.cnblogs.com/libaoquan/p/7109661.html