Hibernate集合排序之内存排序

使用sort属性,我们可以通过在取回结果集后在内存中进行排序,然后返回一个经过排序的结果集合

数据库结构:

create table teamSort (id varchar(32),teamname varchar(32));
create table studentSort (name varchar(32),team_id varchar(32));
insert into teamSort values("1","team1");
insert into studentSort values("a","1");
insert into studentSort values("b","1");
insert into studentSort values("c","1");

pojo: student部分采用set集合,无实体类

package Collection.Sort;

import java.util.Set;

public class Team {
   
private String id;
   
private String teamname;
   
private Set students;
public String getId() {
    
return id;
}

public void setId(String id) {
    
this.id = id;
}

public String getTeamname() {
    
return teamname;
}

public void setTeamname(String teamname) {
    
this.teamname = teamname;
}

public Set getStudents() {
    
return students;
}

public void setStudents(Set students) {
    
this.students = students;
}


}

Team.hbm.xml

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"
>
<!-- 
    Mapping file autogenerated by MyEclipse - Hibernate Tools
-->
<hibernate-mapping>
<class name="Collection.Sort.Team" table="teamSort" >
    
<id name="id" unsaved-value="null">
      
<generator class="uuid.hex"></generator>
    
</id>
    
<property name="teamname" type="string" column="teamname"></property>
    
<!-- 以element内容升序返回 -->
    
<set name="students" table="studentSort" cascade="all" sort="natural">
      
<key column="team_id"></key>
      
<element type="string" column="name"></element>
    
</set>
</class>

</hibernate-mapping>

Hibernate.cfg.xml

<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
          "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
          "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"
>

<!-- Generated by MyEclipse Hibernate Tools.                   -->
<hibernate-configuration>

<session-factory>
    
<property name="connection.username">root</property>
    
<property name="connection.url">
        jdbc:mysql://localhost:3306/schoolproject?characterEncoding=gb2312
&amp;useUnicode=true
    
</property>
    
<property name="dialect">
        org.hibernate.dialect.MySQLDialect
    
</property>
    
<property name="myeclipse.connection.profile">mysql</property>
    
<property name="connection.password">1234</property>
    
<property name="connection.driver_class">
        com.mysql.jdbc.Driver
    
</property>
    
<property name="hibernate.dialect">
        org.hibernate.dialect.MySQLDialect
    
</property>
    
<property name="hibernate.show_sql">true</property>
    
<property name="current_session_context_class">thread</property>
    
<property name="jdbc.batch_size">15</property>
    
<mapping resource="Collection/Sort/Team.hbm.xml" />




</session-factory>

</hibernate-configuration>

测试代码:

package Collection.Sort;


import java.io.File;
import java.util.Iterator;
import java.util.Set;

import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;

public class Test {


    
public static void main(String[] args) {

        String filePath
=System.getProperty("user.dir")+File.separator+"src/Collection/Sort"+File.separator+"hibernate.cfg.xml";
        File file
=new File(filePath);
        System.out.println(filePath);
        SessionFactory sessionFactory
=new Configuration().configure(file).buildSessionFactory();
        Session session
=sessionFactory.openSession();
        Transaction t
=session.beginTransaction();
        
        Team team
=(Team)session.createQuery("from Team t where t.teamname='team1'").uniqueResult();
        Set result
=team.getStudents();
        Iterator iter
=result.iterator();
        
while(iter.hasNext()){
            System.out.println(iter.next());
        }

        
        t.commit();
        
    }


}

运行结果:

Hibernate: select team0_.id as id0_, team0_.teamname as teamname0_ from teamSort team0_ where team0_.teamname='team1'
Hibernate: select students0_.team_id as team1_0_, students0_.name as name0_ from studentSort students0_ where students0_.team_id=?
a
b
c

sort="natural"默认进行升序排列,如果我们想改成降序,则需要写一个类实现Comparator接口如下:

package Collection.Sort;

import java.util.Comparator;

public class Compare implements Comparator {

    
public int compare(Object o1, Object o2) {
        String s1
=(String)o1;
        String s2
=(String)o2;
        
if(s1.equals(s2)){
            
return 0;
        }

        
else if(s1.compareTo(s2)>0){
            
return -1;
        }

        
else{
            
return 1;
        }

    
    }


}

然后更改Team.hbm.xml 配置sort属性

sort="Collection.Sort.Compare"

重新执行测试代码,结果如下:

Hibernate: select team0_.id as id0_, team0_.teamname as teamname0_ from teamSort team0_ where team0_.teamname='team1'
Hibernate: select students0_.team_id as team1_0_, students0_.name as name0_ from studentSort students0_ where students0_.team_id=?
c
b
a

注意:如果有Student实体类,并set中使用one-to-many或many-to-many标签,则比如使用sort="一个实现comparator接口的类"这样排序

原文地址:https://www.cnblogs.com/liaomin416100569/p/9331743.html