java代码实现ZIP格式解压

二话不说，代码奉上：

  1 import java.io.*;
  2 import java.util.*;
  3 import org.apache.tools.zip.*;
  4 
  5 public class AdapterZipFile {
  6     String zipFileName = null;//zip文件的绝对路径
  7     String outputDirectory =null;//zip文件解压缩后的存放路径
  8     ArrayList list = new ArrayList();//文件解压缩后的文件列表绝对路径
  9 
 10 //    public AdapterZipFile(String zipFileName) {
 11 //        if(zipFileName == null){
 12 //            return;
 13 //        }
 14 //        this.zipFileName = zipFileName.replace("/","\\");
 15 //        unZipFile();
 16 //    }
 17 
 18     //初始化
 19     public AdapterZipFile(String zipFileName, String outputDirectory){  //可以实现压缩文件中包含子文件夹的情况
 20         if(zipFileName == null){
 21             return;
 22         }
 23         this.zipFileName = zipFileName;
 24         if(outputDirectory != null){
 25              this.outputDirectory = outputDirectory;
 26         }else{
 27             this.outputDirectory = zipFileName.substring(0,
 28                     zipFileName.replace('\\', '/').lastIndexOf("/"));
 29         }
 30        // unZipFile();
 31     }
 32 
 33    //创建目录
 34     private void createDirectory(String directory, String subDirectory) {
 35         String dir[];
 36         File fl = new File(directory);
 37         try {
 38             if (subDirectory == "" && fl.exists() != true)
 39                 fl.mkdirs();
 40             else if (subDirectory != "") {
 41                 dir = subDirectory.replace("\\","/").split("/");
 42                 for (int i = 0; i < dir.length; i++) {
 43                     File subFile = new File(directory + File.separator + dir[i]);
 44                     if (!subFile.exists())
 45                         subFile.mkdir();
 46                     directory += File.separator + dir[i];
 47                 }
 48             }
 49         }catch (Exception ex) {
 50             System.out.println(ex.getMessage());
 51         }
 52     }
 53 
 54     //解压缩文件
 55     //如果outputDierctory为null，解压到zipFileName文件的当前目录下
 56     public void unZipFile() {
 57         File file = new File(zipFileName);
 58         if (!file.exists()) {
 59             return;
 60         }
 61         createDirectory(outputDirectory, "");
 62 
 63         try {
 64             ZipFile zipFile = new ZipFile(zipFileName);
 65             Enumeration e = zipFile.getEntries();
 66             ZipEntry zipEntry = null;
 67             while (e.hasMoreElements()) {
 68                 zipEntry = (ZipEntry) e.nextElement();
 69                 if (zipEntry.isDirectory()) {
 70                     String name = zipEntry.getName();
 71                     name = name.substring(0, name.length() - 1);
 72                     File f = new File(outputDirectory + File.separator + name);
 73                     f.mkdir();
 74                 } else {
 75                     String fileName = zipEntry.getName();
 76                     fileName = fileName.replace('\\', '/');
 77                     //文件在多层目录下 这时需要创建目录如：d1/d2/1.txt
 78                     if (fileName.indexOf("/") != -1) {
 79                         createDirectory(outputDirectory, fileName.substring(0,
 80                                 fileName.lastIndexOf("/")));
 81                         fileName = fileName.substring(
 82                                 fileName.lastIndexOf("/") + 1, fileName
 83                                 .length());
 84                     }
 85 
 86                     list.add(outputDirectory + File.separator
 87                                       + zipEntry.getName());
 88                     File f = new File(outputDirectory + File.separator
 89                                       + zipEntry.getName());
 90 
 91                     f.createNewFile();
 92                     InputStream in = zipFile.getInputStream(zipEntry);
 93                     FileOutputStream out = new FileOutputStream(f);
 94 
 95                     byte[] by = new byte[1024*1024*6];
 96                     int c;
 97                     while ((c = in.read(by)) != -1) {
 98                         out.write(by, 0, c);
 99                     }
100                     out.close();
101                     in.close();
102                 }
103             }
104         } catch (Exception ex) {
105             System.out.println(ex.getMessage());
106         }
107     }
108 
109    //返回zip文件解压撒后文件列表的绝对路径
110     public ArrayList GetZipFileList(){
111         return list;
112     }
113     public static void main(String[] args) {
114          AdapterZipFile uzip=new AdapterZipFile("F:/lucene视频和示例.zip","F:/2013");
115          long a=System.currentTimeMillis();
116          uzip.unZipFile();
117          long b=System.currentTimeMillis();
118          System.out.println("文件解压耗时"+(b-a) +"毫秒");
119     }
120 }

解压可以根据目标文件的大小，适时的调整缓存流的大小。刚刚测试了下把缓存流设置在1024还是最佳的，解压900MB左右的ZIP文件大概需要22S左右，当然这可能和你自己所用的电脑有一点关系，但是我自己也用了解压软件测试了下，大概在10s左右，这说明上面的代码还是有很大优化的空间的，希望看到这篇博文的同学，可以和我交流下！！！！！一起学习，一起进步！@！！！！