Search a 2D Matrix

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

  • Integers in each row are sorted from left to right.
  • The first integer of each row is greater than the last integer of the previous row.

For example,

Consider the following matrix:

[
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]

Given target = 3, return true.

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 Array Binary Search
 
class Solution {
public:
    bool searchMatrix(vector<vector<int> > &matrix, int target) {
        int i=0,j=matrix[0].size()-1;
        while(i<matrix.size() && j>=0){
            if(matrix[i][j]==target)
                return true;
            else if(matrix[i][j]>target)
                j--;
            else
                i++;
        }
        return false;
    }
};
原文地址:https://www.cnblogs.com/li303491/p/4079900.html