直角三角形填数



#include <stdio.h>
#include <string.h>
int map[100][100];

int main()
{
	memset(map, 0, sizeof(map));
	int n, i, j,count;
	int x = 1, y = 0;
	int tot = 1;
	scanf("%d", &n);
	count = (1 + n) * n / 2;
	//printf("%d\n\n",count);
	while(tot != count+1)
	{
		while(y < n && !map[x][y+1])//横行
		{
			map[x][++y] = tot++;
		}
		if(tot == count+1) break;
		
		while(x < n && !map[x+1][y-1])//斜行
		{
			map[++x][--y] = tot++;
		}
		if(tot == count+1) break;
		
		while(y > 0 && !map[x-1][y])//竖行
		{
			map[--x][y] = tot++;
		}
		if(tot == count+1) break;
	}
	
	for(i = 1; i <= n; i++)
	{
		for(j = 1; j <= n; j++)
		{
			if(map[i][j] != 0)
			{
				printf("%-4d",map[i][j]);
			}
		}
		printf("\n");
	}
	return 0;
}


原文地址:https://www.cnblogs.com/lgh1992314/p/5835162.html