报错
ProgrammingError: You must not use 8-bit bytestrings unless you use a text_factory that can interpret 8-bit bytestrings (like text_factory = str). It is highly recommended that you instead just switch your application to Unicode strings
修正方法,按照提示
加入
conn.text_factory = str
或者将应用切换为Unicode 字符
conn.text_factory = lambda x: unicode(x, ‘utf-8′, ‘ignore’)
By default text_factory is set to unicode(), which will use the current default encoding (ascii on my machine)
或者插入字符串前,强制转换为unicode
请查看 PySQLite的文档
http://pysqlite.googlecode.com/svn/doc/sqlite3.html#sqlite3.Connection.text_factory
http://docs.python.org/library/sqlite3.html#sqlite3.Connection.text_factory
请看类似的修正
http://bazaar.launchpad.net/~francesco-marella/entertainer/fix-bug-315247/revision/407?remember=407
http://issues.roundup-tracker.org/issue2277204
这个问题只在
Python 2.6/sqlite3 或者 Python 3.x中出现
我在Debian Squeeze中默认使用 Python 2.5 就没事
在 Ubuntu 10.04 中使用Python 2.6 就有这个问题
在Django中是这么修复的
if Database.version_info >= (2,4,1):
# Starting in 2.4.1, the str type is not accepted anymore, therefore,
# we convert all str objects to Unicode
# As registering a adapter for a primitive type causes a small
# slow-down, this adapter is only registered for sqlite3 versions
# needing it.
Database.register_adapter(str, lambda s:s.decode(‘utf-8′))
In Py3, anything you do “this” or use str(), you are using unicode strings.
The problem appears to be that you are passing bytestrings to sqlite; things
created with b”this” or bytes(), or read from a file as bytes and not
decoded before passing it to the database.
To really help further, you should provide the line that threw that warning
and show where any variables in it come from. As for that error message, I
believe it means text_factory = bytes.