Saving Tang Monk II

题目链接：http://hihocoder.com/contest/acmicpc2018beijingonline/problem/1

AC代码：

#include<bits/stdc++.h>
using namespace std;
# define inf 0x3f3f3f3f
# define maxn 100+10
# define ll long long
int n,m;
char a[maxn][maxn];
int f[2][4]= {{1,-1,0,0},{0,0,1,-1}};
int vis[maxn][maxn][10];
struct node
{
    int x,y,b,step;
    node() {}
    node(int xx,int yy,int tt,int ww)
    {
        x=xx;
        y=yy;
        b=tt;
        step=ww;
    }
    friend bool operator < (node a,node b)
    {
        return a.step>b.step;
    }
};
void bfs(int t1,int t2)
{
    priority_queue<node>q;
    memset(vis,0,sizeof(vis));
    q.push(node(t1,t2,0,0));
    vis[t1][t2][0]=1;
    while(!q.empty())
    {
        node temp=q.top();
        q.pop();
        // cout<<temp.x<<" "<<temp.y<<" "<<temp.b<<" "<<temp.step<<endl;
        for(int i=0; i<4; i++)
        {
            node temp2;
            int x=temp.x+f[0][i];
            int y=temp.y+f[1][i];
            if(x<=0||x>n||y<=0||y>m)continue;
            temp2.x=x;
            temp2.y=y;
            temp2.b=temp.b;
            temp2.step=temp.step+1;
            if(a[x][y]=='B')
            {
                temp2.b=min(temp2.b+1,5);
            }
            else if(a[x][y]=='P')
            {
                temp2.step=max(temp2.step-1,0);
            }
            else if(a[x][y]=='#')
            {
                if(temp.b==0)continue;
                temp2.b=max(temp2.b-1,0);
                temp2.step++;
            }
            else if(a[x][y]=='T')
            {
                printf("%d
",temp2.step);
                return ;
            }
            if(vis[x][y][temp2.b])continue;
            vis[x][y][temp2.b]=1;
            q.push(temp2);
        }
    }
    printf("%d
",-1);
}
int main()
{
    while(~scanf("%d%d",&n,&m))
    {
        if(n+m==0)break;
        int t1,t2;
        getchar();
        for(int i=1; i<=n; i++)
        {
            for(int j=1; j<=m; j++)
            {
                scanf("%c",&a[i][j]);
                if(a[i][j]=='S')
                {
                    t1=i;
                    t2=j;
                }
            }
            getchar();
        }
        bfs(t1,t2);
    }
    return 0;
}