codeforces 887A Div. 64 思维模拟

Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.

Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisible by 64, in the binary numerical system.

Input

In the only line given a non-empty binary string s with length up to 100.

Output

Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise.

Examples

input

100010001

output

yes

input

output

no

Note

In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.

You can read more about binary numeral system representation here: https://en.wikipedia.org/wiki/Binary_system

思路：

先统计有多少个0，然后从前往后数，遇到第一个1时，判断后面剩余的0的个数是否大于等于6

代码：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main() {
 4     string s;
 5     cin>>s;
 6     int len=s.length();
 7     int cnt_zero=0;
 8     int cnt_one=0;
 9     for(int i=0;i<len;++i) {
10         if(s[i]=='0') cnt_zero++;
11     }
12     for(int i=0;i<len;++i) {
13         if(s[i]=='0') cnt_zero--;
14         if(s[i]=='1') break;
15     }
16     if(cnt_zero>=6) cout<<"yes"<<endl;
17     else cout<<"no"<<endl;
18     return 0;
19 }

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codeforces 887A Div. 64 思维 模拟

codeforces 887A Div. 64 思维模拟