PAT 1065. A+B and C (64bit) (20)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

源代码：

注意a<0,b<0但是和为0 的情况

#include <cstdio>
int main() {
    int T,tcase=1;
    scanf("%d",&T);
    while(T--) {
        long long a,b,c;
        scanf("%lld%lld%lld",&a,&b,&c);
        long long res=a+b;
        bool flag;
        if(a>0&&b>0&&res<0) flag=true;
        else if(a<0&&b<0&&res>=0) flag=false;
        else if(res>c) flag=true;
        else flag=false;
        if(flag) printf("Case #%d: true
",tcase++);
        else printf("Case #%d: false
",tcase++);
    }
    return 0;
}