python 解决url编译

from urllib import parse


s = parse.unquote("%7B%22name%22%3A%22joe%22%2C%22age%22%3A%2223%22%7D")
print(s)
import json

b = json.loads(s)
print(type(b))
print(b['name'])

  

原文地址:https://www.cnblogs.com/leigepython/p/10119510.html