监控服务是否正常运行

监控服务是否正常,实现邮件报警

#监控端口号,实现查看服务是否运行

方法一:
def sendmail(message, ip): import smtplib from email.mime.text import MIMEText from email.header import Header sender = '18618250232@163.com' receiver = 'lizhao_dc@126.com' subject = '%s报警' % ip username = '18618250232@163.com' password = 'xxxx' msg = MIMEText(message, 'plain', 'utf-8') msg['Subject'] = Header(subject, 'utf-8') msg['From'] = 'Tim<18618250232@163.com>' msg['To'] = "lizhao_dc@126.com" smtp = smtplib.SMTP() smtp.connect('smtp.163.com') smtp.login(username, password) smtp.sendmail(sender, receiver, msg.as_string()) smtp.quit()
方法二:
import re import socket socket.setdefaulttimeout(1) server = socket.socket() host_list = ['192.168.4.145:5555','127.0.0.1:8888','2.2.2.2:80','3.3.3.3:3333'] for info in host_list: ip = re.compile('(.*?):(.*)').search(info).group(1) port = re.compile('(.*?):(.*)').search(info).group(2) res = server.connect_ex((ip, int(port))) if res != 0: print('%s不通' % port, ip)
原文地址:https://www.cnblogs.com/leading-net/p/10582540.html