Play Modules Morphia 1.2.9a 之 Aggregation and Group aggregation

聚合 和 分组聚合:

PlayMorphia 它提供了基于开发人员models的友好接口

设想你定义了一个model。class Sales: 


@Entity public class Sales extends Model {
    public String employeeId;
    public String department;
    public String region;
    public int amount;
}


聚合:如今你能够在Sales模型上做聚合操作,以下是一些详细演示样例:

long total = Sales.count(); // also Sales.q().count();
long cntIT = Sales.q().filter("department", "IT").count();
long cntAU = Sales.q().filter("region", "AU").count();
long cntAuIt = Sales.find("region, department", "AU", "IT").count();


求和:

long sum = Sales._sum("amount"); // also Sales.q().sum("amount");
long sumIT = Sales.find("department", "IT").sum("amount");
long sumAU = Sales.find("region", "AU").sum("amount");
long sumAuIt = Sales.find("region department", "AU", "IT").sum("amount");

最大值:

long max = Sales._max("amount"); // also Sales.q().max("amount");
long maxIT = Sales.find("department", "IT").max("amount");
long maxAU = Sales.find("region", "AU").max("amount");
long maxAuIt = Sales.find("region department", "AU", "IT").max("amount");

最小值:

long min = Sales._min("amount"); // also Sales.q().min("amount");
long minIT = Sales.find("department", "IT").min("amount");
long minAU = Sales.find("region", "AU").min("amount");
long minAuIt = Sales.find("region department", "AU", "IT").min("amount");

分组聚合:

每个聚合都会相应一个分组聚合的接口,就像SQL中的group by语句


分组计数:

// group by region
AggregationResult byRegion = Sales.groupCount("region");
System.out.println("AU count: " + byRegion.get("region", "AU");
// group by department
AggregationResult byDep = Sales.groupCount("department");
System.out.println("IT count: " + byDep.get("department", "IT");
// group by region and department
AggregationResult byRegionDep = Sales.groupCount("region, department");
System.out.println("IT count: " + byRegionDep.get("department, region", "IT", "AU");


分组求和:

// group by region
AggregationResult byRegion = Sales.groupSum("region");
System.out.println("AU sum: " + byRegion.get("region", "AU");
// group by department
AggregationResult byDep = Sales.groupSum("department");
System.out.println("IT sum: " + byDep.get("department", "IT");
// group by region and department
AggregationResult byRegionDep = Sales.groupSum("region, department");
System.out.println("IT sum: " + byRegionDep.get("department, region", "IT", "AU");

分组求最大值:

// group by region
AggregationResult byRegion = Sales.groupMax("region");
System.out.println("AU max: " + byRegion.get("region", "AU");
// group by department
AggregationResult byDep = Sales.groupMax("department");
System.out.println("IT max: " + byDep.get("department", "IT");
// group by region and department
AggregationResult byRegionDep = Sales.groupMax("region, department");
System.out.println("IT max: " + byRegionDep.get("department, region", "IT", "AU");


分组求最小值:

// group by region
AggregationResult byRegion = Sales.groupMin("region");
System.out.println("AU min: " + byRegion.get("region", "AU");
// group by department
AggregationResult byDep = Sales.groupMin("department");
System.out.println("IT min: " + byDep.get("department", "IT");
// group by region and department
AggregationResult byRegionDep = Sales.groupMin("region, department");
System.out.println("IT min: " + byRegionDep.get("department, region", "IT", "AU");


原文链接:http://www.playframework.com/modules/morphia-1.2.9/statistics

原文地址:https://www.cnblogs.com/lcchuguo/p/4792910.html