计算系数

二项式定理

(ax+by)^k%p=sigma(i=0,k) c[i]*x^i*y^(k-i)    c[i]=a^i*b^(k-i)*C(i,k)

要开long long虽然有模数,但在计算加法时可能会溢出使答案不正确

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 using namespace std;
 5 const long long maxn=1007;
 6 const long long mod=10007;
 7 long long f[maxn+7][maxn+7],ans;
 8 long long a,b,k,n,m;
 9 void maketable(){
10     for(long long i=0;i<=maxn;i++)
11         for(long long j=1;j<=maxn;j++)
12             f[i][j]=1;
13     for(long long i=2;i<=k;i++)
14         for(long long j=2;j<=i;j++)
15             f[i][j]=(f[i-1][j-1]+f[i-1][j])%mod;     
16 }
17 long long quick(long long a,long long b,long long p){
18     long long ans=1;
19     for( ;b;b>>=1,a=(a*a)%p){
20         if(b&1==1){
21             ans=(ans*a)%p;
22         }
23     }
24     return ans;
25 }
26 int main(){
27     cin>>a>>b>>k>>n>>m;
28     maketable();
29     ans=(quick(a,n,mod)*quick(b,m,mod)*f[k][n+1])%mod;
30     cout<<ans<<endl;
31     return 0; 
32 } 
原文地址:https://www.cnblogs.com/lcan/p/9478361.html