hdu-1012-u Calculate e(水题)

#include <iostream> 
using namespace std;
int main() {
    int jiecheng[10];
    jiecheng[0] = jiecheng[1] = 1;
    for (int i=2; i<10; i++) {
        jiecheng[i] = jiecheng[i-1] * i;
    }
    printf("n e
");
    printf("- -----------
");
    printf("0 1
");
    printf("1 2
");
    printf("2 2.5
");
    double num[10];
    num[2] = 2.5;
    for (int i=3; i<10; i++) {
        num[i] = 1.0/jiecheng[i] + num[i-1];
        printf("%d %.9lf
", i,num[i]);
    }
    return 0;
}