jQuery获取Ajax函数的返回值

参考自:

http://blog.csdn.net/crx05/article/details/7362252

function test() {
                var myText  = "";
                myText = $.ajax({
                    type: "POST",
                    url: "/dragable/demo/test",
                    async:false,
                    data: {},
                   // dataType: "json",
                    dataType: "text",
                    success: function(data){
                                            
                    }}).responseText;
                alert(myText);
}
原文地址:https://www.cnblogs.com/langdangyunliu/p/4487322.html