HDU 2672 god is a girl (字符串处理,找规律,简单)

题目

//1,1,2,3,5,8,13,21,34,55……

//斐波纳契数列

#include<math.h>
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;

int main()
{
    char str[10010];
    int len,i,a,b,c;
    while(gets(str))
    {
        len = strlen(str);
        a=0;
        b=c=1;
        for(i=0;i<len;i++)
        {
            if(str[i] >= 'A' && str[i] <= 'Z')
            {
                int ii = (str[i] - 'A' + c) % 26 ;
                printf("%c",ii + 'A');
                c=(a+b)%26;
                a=b;
                b=c;
            }
            else
            {
                printf("%c",str[i]);
            }
        }
        puts("");

    }
    return 0;

}
View Code
一道又一道,好高兴!
原文地址:https://www.cnblogs.com/laiba2004/p/3801332.html