PKU 1458 Common Subsequence(最长公共子序列,dp,简单)

题目

 同:ZJU 1733,HDU 1159

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

int dp[1010][1010];
int main()
{
    char a[1010], b[1010];    
    int la, lb;
    while(scanf("%s%s", a, b) != EOF)
    {
        memset(dp, 0, sizeof(dp));
        la = strlen(a), lb = strlen(b);
        for(int i = 0; i < la; i++)
        {
            for(int j = 0; j < lb; j++)
            {
                if(a[i] == b[j])
                {
                    dp[i+1][j+1] = dp[i][j] + 1;
                }
                else
                {
                    dp[i+1][j+1] = max(dp[i+1][j], dp[i][j+1]);
                }
            }
        }
        printf("%d
", dp[la][lb]);
    }
    return 0;
}
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一道又一道,好高兴!
原文地址:https://www.cnblogs.com/laiba2004/p/3631607.html