tiles框架的definition讲解

<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE tiles-definitions PUBLIC

"-//Apache Software Foundation//DTD Tiles Configuration 1.1//EN"

    "http://jakarta.apache.org/struts/dtds/tiles-config_1_1.dtd">

<tiles-definitions>

    <!--classicLayout-->

    <definition name="layout.base" path="/layouts/classicLayout.jsp">

        <put name="title" value="++welcome" />

        <put name="header" value="/template/header.jsp" />

        <put name="menu" value="/template/menu.jsp" />

        <put name="footer" value="/template/footer.jsp" />

        <put name="body" value="/template/body.jsp" />

    </definition>

 

    <!-- 后台管理 -->

    <definition name="layout.backmanager" path="/layouts/classicLayout.jsp">

        <put name="title" value="Back Manager" />

        <put name="header" value="/template/back_header.jsp" />

        <put name="menu" value="/back/menu.jsp" />

        <put name="body" value="/back/main.jsp" />

        <put name="footer" value="/template/footer.jsp" />

    </definition>

 

    <!-- 前台首页 -->

    <definition name="front.main" extends="layout.base">

    </definition>

 

    <!-- 后台管理-首页 -->

    <definition name="back.main" extends="layout.backmanager">

    </definition>

    

    <!-- 后台管理-新增用户 -->

    <definition name="back.addUser" extends="layout.backmanager">

        <put name="title" value="Add User" />

        <put name="body" value="/back/addUser.jsp" />

    </definition>

</tiles-definitions>

上面转自http://blog.csdn.net/qjyong/article/details/1721253

back.addUser继承了layout.backmanager

标题将被替换成Add User

body将被替换成addUser.jsp

<definition name="base-definition" path="/layout.jsp"> 
    <put name="sidebar" value="sidebar.jsp"/> 
    <put name="header" value="header.jsp"/> 
    <put name="content" value=""/> 
    <put name="footer" value="footer.jsp"/> 
</definition> 

<definition name="index-definition" extends="base-definition"> 
    <put name="content" value="indexContent.jsp"/> 
</definition> 

这样一来，每次增加一个新的类似indexContent的页面时，只需要配置一个新的继承自base-definition的definition就OK了