neo4j 查找每个标签的所有属性

unwind ['医保疾病名称','症状','体征'] as lab
match (n) where any(label in labels(n) WHERE label=lab) with lab,keys(n) as kk
unwind kk as k
return lab,collect(distinct k)

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原文地址：https://www.cnblogs.com/kwzblog/p/14107633.html