【noi 2.6_747】Divisibility(DP)

这题题意与前面的“判断整除”重复了。具体解释可看我这篇的博文。

http://www.cnblogs.com/konjak/p/5936738.html

 1 #include<cstdio>
 2 #include<cstdlib>
 3 #include<cstring>
 4 #include<iostream>
 5 using namespace std;
 6 #define N 10010
 7 #define K 110
 8 int a[N],f[N][K];
 9 
10 int main()
11 {
12     int i,j,n,k;
13     scanf("%d%d",&n,&k);
14     for (i=1;i<=n;i++)
15       scanf("%d",&a[i]),a[i]%=k;
16     f[0][0]=1;
17     for (j=1;j<k;j++) f[0][j]=0;
18     for (i=1;i<=n;i++)
19      for (j=0;j<k;j++)
20      {
21        int x=(j-a[i]+k)%k,y=(j+a[i]+k)%k;
22        f[i][j]=f[i-1][x]|f[i-1][y];
23      }
24     if (f[n][0]) printf("Divisible
");
25     else printf("Not divisible
");
26     return 0;
27 }
原文地址:https://www.cnblogs.com/konjak/p/5963028.html