1009. Product of Polynomials

1009. Product of Polynomials (25)

时间限制
400 ms
内存限制
32000 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

This time, you are supposed to find A*B where A and B are two polynomials.

Input Specification:

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10, 0 <= NK < ... < N2 < N1 <=1000.

Output Specification:

For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.

Sample Input
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output
3 3 3.6 2 6.0 1 1.6
  1 #include <iostream>
2 #include <fstream>
3 #include <vector>
4 #include <string>
5 #include <algorithm>
6 #include <map>
7 #include <stack>
8 #include <cmath>
9 #include <queue>
10 #include <set>
11
12
13 using namespace std;
14
15
16 class Term
17 {
18 public :
19 int exponent;
20 double coefficient;
21 };
22
23
24 bool operator< ( const Term &t1 , const Term &t2 )
25 {
26 return t1.exponent > t2.exponent;
27 }
28
29 //bool operator== ( const Term &t1 , const Term &t2 )
30 //{
31 // return t1.exponent == t2.exponent;
32 //}
33
34
35 class Polynomial
36 {
37 public :
38 vector<Term> terms;
39
40 void addTerm( const Term &term )
41 {
42
43 for( int i = 0 ; i < this->terms.size() ; ++i )
44 {
45 if( this->terms[i].exponent == term.exponent )
46 {
47 this->terms[i].coefficient += term.coefficient;
48 if( this->terms[i].coefficient == 0 )
49 {
50 this->terms.erase(this->terms.begin() + i);
51 }
52 return;
53 }
54 }
55
56 this->terms.push_back(term);
57
58 }
59
60
61 Polynomial times( const Polynomial &poly )
62 {
63 Polynomial result;
64
65 for( int i = 0 ; i < poly.terms.size() ; ++i )
66 {
67 for( int j = 0 ; j < this->terms.size() ; ++j )
68 {
69 Term term;
70 term.exponent = this->terms[j].exponent + poly.terms[i].exponent;
71 term.coefficient = this->terms[j].coefficient * poly.terms[i].coefficient;
72
73 result.addTerm(term);
74 }
75 }
76
77 return result;
78 }
79
80
81
82 void toString()
83 {
84
85
86 sort(this->terms.begin() , this->terms.end());
87
88 printf("%d" , this->terms.size());
89
90 for( int i = 0 ; i < this->terms.size() ; ++i )
91 {
92 printf( " %d %.1f" , this->terms[i].exponent , this->terms[i].coefficient );
93 }
94
95 cout << endl;
96 }
97 };
98
99
100
101
102 int main()
103 {
104
105
106
107 Polynomial p1;
108 Polynomial p2;
109 int n;
110 int m;
111
112 cin >> n;
113
114 for( int i = 0 ; i < n ; ++i )
115 {
116 Term term;
117
118 cin >> term.exponent >> term.coefficient;
119
120 p1.addTerm(term);
121 }
122
123 cin >> m;
124
125 for( int i = 0 ; i < m ; ++i )
126 {
127 Term term;
128
129 cin >> term.exponent >> term.coefficient;
130
131 p2.addTerm(term);
132 }
133
134 p1.times(p2).toString();
135
136 return 0;
137 }


原文地址:https://www.cnblogs.com/kking/p/2331814.html