冒泡算法

# 方法1
a = [1,7,4,89,34,2]
for i in range(1,len(a)):  # a[0],a[1],a[2]... 取不了len(a)
    for j in range(i+1):  # a[0],a[1],a[i+1]
        if a[j]>a[i] :
            a[j],a[i] = a[i],a[j]

print(a)

# 方法2 相邻两元素比较
def bubbleSort1(a1):
    for i in range(1,len(a1)-1):  # 跑n-1趟,循环负责设置冒泡排序进行的次数
        for j in range(len(a1)-i):  # j为列表下标,到i-1为止
            if a1[j]>a1[j+1]:
                a1[j],a1[j+1] = a1[j+1],a1[j]
    print(a1)


bubbleSort1([1,7,4,89,34,2])
原文地址:https://www.cnblogs.com/kite123/p/12505598.html