[HDOJ1083]Courses(二分图最大匹配,匈牙利算法)

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1083

题意:没咋仔细看,感觉是n个学生m个课程,学生只能选一门课,每门课只能有一个学生选。给一个图描述学生和课程的喜好关系,问学生能不能都选到课。

按照学生和课程直接建图,做最大匹配,结果如果和学生数相同则说明都可以选到课。

  1 /*
  2 ━━━━━┒ギリギリ♂ eye!
  3 ┓┏┓┏┓┃キリキリ♂ mind!
  4 ┛┗┛┗┛┃\○/
  5 ┓┏┓┏┓┃ /
  6 ┛┗┛┗┛┃ノ)
  7 ┓┏┓┏┓┃
  8 ┛┗┛┗┛┃
  9 ┓┏┓┏┓┃
 10 ┛┗┛┗┛┃
 11 ┓┏┓┏┓┃
 12 ┛┗┛┗┛┃
 13 ┓┏┓┏┓┃
 14 ┃┃┃┃┃┃
 15 ┻┻┻┻┻┻
 16 */
 17 #include <algorithm>
 18 #include <iostream>
 19 #include <iomanip>
 20 #include <cstring>
 21 #include <climits>
 22 #include <complex>
 23 #include <fstream>
 24 #include <cassert>
 25 #include <cstdio>
 26 #include <bitset>
 27 #include <vector>
 28 #include <deque>
 29 #include <queue>
 30 #include <stack>
 31 #include <ctime>
 32 #include <set>
 33 #include <map>
 34 #include <cmath>
 35 using namespace std;
 36 #define fr first
 37 #define sc second
 38 #define cl clear
 39 #define BUG puts("here!!!")
 40 #define W(a) while(a--)
 41 #define pb(a) push_back(a)
 42 #define Rint(a) scanf("%d", &a)
 43 #define Rll(a) scanf("%I64d", &a)
 44 #define Rs(a) scanf("%s", a)
 45 #define Cin(a) cin >> a
 46 #define FRead() freopen("in", "r", stdin)
 47 #define FWrite() freopen("out", "w", stdout)
 48 #define Rep(i, len) for(int i = 0; i < (len); i++)
 49 #define For(i, a, len) for(int i = (a); i < (len); i++)
 50 #define Cls(a) memset((a), 0, sizeof(a))
 51 #define Clr(a, x) memset((a), (x), sizeof(a))
 52 #define Full(a) memset((a), 0x7f7f7f, sizeof(a))
 53 #define lrt rt << 1
 54 #define rrt rt << 1 | 1
 55 #define pi 3.14159265359
 56 #define RT return
 57 #define lowbit(x) x & (-x)
 58 #define onecnt(x) __builtin_popcount(x)
 59 typedef long long LL;
 60 typedef long double LD;
 61 typedef unsigned long long ULL;
 62 typedef pair<int, int> pii;
 63 typedef pair<string, int> psi;
 64 typedef pair<LL, LL> pll;
 65 typedef map<string, int> msi;
 66 typedef vector<int> vi;
 67 typedef vector<LL> vl;
 68 typedef vector<vl> vvl;
 69 typedef vector<bool> vb;
 70 
 71 const int maxn = 330;
 72 int nu, nv;
 73 int G[maxn][maxn];
 74 int linker[maxn];
 75 bool vis[maxn];
 76 
 77 bool dfs(int u) {
 78     For(v, 1, nv+1) {
 79         if(G[u][v] && !vis[v]) {
 80             vis[v] = 1;
 81             if(linker[v] == -1 || dfs(linker[v])) {
 82                 linker[v] = u;
 83                 return 1;
 84             }
 85         }
 86     }
 87     return 0;
 88 }
 89 
 90 int main(){
 91     // FRead();
 92     int T, k, v;
 93     Rint(T);
 94     W(T) {
 95         Cls(G);
 96         Rint(nu); Rint(nv);
 97         For(u, 1, nu+1) {
 98             Rint(k);
 99             W(k) {
100                 Rint(v);
101                 G[u][v] = 1;
102             }
103         }
104         int ret = 0;
105         Clr(linker, -1);
106         For(u, 1, nu+1) {
107             Cls(vis);
108             if(dfs(u)) ret++;
109         }
110         if(ret == nu) puts("YES");
111         else puts("NO");
112     }
113     RT 0;
114 }
原文地址:https://www.cnblogs.com/kirai/p/5803893.html