acm_hdu Problem Archive 1002

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void add(char *a, char *b,char *sum)//字符串a要比字符串b长,或相等
{
int len_a = strlen(a);
int len_b = strlen(b);
char tmp[len_a];
int offset = len_a-len_b;
strncpy(tmp+offset,b,len_b);//后面len_b长度复制,前面offset长度填充字符‘0’
for (int i=0; i<offset; i++)
tmp[i]='0';
//tmp[len_a] = '';
//printf("tmp=%s ", tmp);

int flag = 0;
int top = 0;
for (int i=len_a-1; i>=0; i--)
{
int res = (a[i]-48) + (tmp[i]-48) + flag;
if (res >= 10)
{
flag = 1;
res -= 10;
}
else
flag = 0;

sum[i] = res+48;
if (i == 0)//设置最高位是1还是0,并作为返回值,控制main函数中是否打印出来
{
if (flag == 1)
top = 1;
else
top = 0;
}
}
sum[len_a] = '';
if (top == 1)//最高位为1打印出来,否则不打印
printf("%d%s ",top,sum);
else
printf("%s ",sum);
}

int main()
{
int n = 0;
scanf("%d ",&n);//%d后面的空格不要丢了,要不然enter会被gets函数(如果用)读入。
//控制串的空白字符使在输入流中跳过一个或多个空白字符.
for (int i=0; i<n; i++)
{
char a[1000];
char b[1000];
char sum[1000];
scanf("%s %s",a,b);//scanf自动在a,b结尾加'',若输入把a,b塞满了则NUL在数组外面+1位置
//printf("a=%s b=%s ", a,b);

printf("Case %d: ",i+1);
printf("%s + %s = ",a,b);
int len_a = strlen(a);
int len_b = strlen(b);
if (len_a >= len_b)
add(a,b,sum);
else
add(b,a,sum);
if (i<n-1)
printf(" ");
}
return 0;
}

原文地址:https://www.cnblogs.com/kimihe/p/4509967.html