简单的MySQL主从状态监控

#!/bin/bash

mysql_c="mysql -uroot -p123456"

$mysql_c -e "show slave statusG" > /usr/local/mysql_s.log

n1=`wc -l /usr/local/mysql_s.log |awk '{print $1}'`

if [ $n1 -gt 0 ]
then
        y1=`grep 'Slave_IO_Running:' /usr/local/mysql_s.log |awk -F : '{print $2}' |sed 's/ //'`
        y2=`grep 'Slave_SQL_Running' /usr/local/mysql_s.log |awk -F : '{print $2}' |sed 's/ //'`

        if [ $y1 == "No" ] || [ $y2 == "No" ]
        then
                echo '有问题'
        else
                echo '没问题'
        fi
fi
原文地址:https://www.cnblogs.com/kgdxpr/p/12306537.html