CodeForces 116C 【BFS】

思路:

求所有树的最大高度?

注意:所有树从树根开始?

#include <bits/stdc++.h>
using namespace std;
typedef long long LL;


struct asd{
	int to;
	int next;
}e[2500];
int head[2500],tol;
int pre[2500];
int n;

void add(int u,int v)
{
	e[tol].to=v;
	e[tol].next=head[u];
	head[u]=tol++;
}

bool vis[2500];
struct ad{
	int w;
	int step;
};
int BFS(int s)
{
	int res=0;
	vis[s]=1;
	ad now,nex;
	now.step=1;
	now.w=s;
	queue<ad>q;
	q.push(now);
	while(!q.empty())
	{
		now=q.front();
		q.pop();
		res=max(now.step,res);
		int u=now.w;
		for(int i=head[u];~i;i=e[i].next)
		{
			int v=e[i].to;
			if(vis[v]) continue;
			vis[v]=1;
			nex.w=v;
			nex.step=now.step+1;
			q.push(nex);
		}
	}
	return res;
}

int main()
{
	int x;
	scanf("%d",&n);
	tol=0;
	memset(head,-1,sizeof(head));
	memset(vis,0,sizeof(vis));
	memset(pre,0,sizeof(pre));
	for(int i=1;i<=n;i++)
	{
		scanf("%d",&x);
		if(x==-1) continue;
		add(x,i);
		pre[i]++;
	}
	int ans=0;
	for(int i=1;i<=n;i++){
		if(!pre[i])
		{
			ans=max(ans,BFS(i));
		}
	}
	printf("%d
",ans);
	return 0;
}


原文地址:https://www.cnblogs.com/keyboarder-zsq/p/6777355.html