【c实现，vc6调试通过】给出一字符串指针，计算出字符串指针中单词数

 1 #include <stdio.h>
 2 
 3 /*
 4     给出一字符串指针，计算出字符串指针中单词数，
 5     单词不包括'.',',',';','?','_','"'，由0-9数字或26个字母组成
 6     by zww @ 2013.09.26
 7     vc 6.0编译通过
 8 */
 9 
10 unsigned int get_string_word_cnt(const char* pStr)
11 {
12     unsigned int iCnt= 0;
13     unsigned int iCharCnt = 0;
14     const char* p = pStr;
15 
16     if (NULL == pStr)
17     {
18         return 0;
19     }
20 
21     while ('' != *p)
22     {
23         if (('.' == *p)
24             || (',' == *p)
25             || (';' == *p)
26             || ('?' == *p)
27             || (' ' == *p)
28             || ('_' == *p)
29             || ('"' == *p))
30         {
31             printf("[%c]",*p);
32             iCharCnt=0;
33         }  
34         else if (!((*p >= 'a'&& *p<='z')
35             || (*p >='A' && *p<='Z')
36             || (*p >= '0' && *p <='9')))
37         {
38             printf("[%c]",*p);
39             iCharCnt = 0;
40         }
41         else if (0 == iCharCnt)
42         {
43             iCharCnt++;
44             iCnt++;
45         }
46 
47         p++; 
48     }
49 
50     return iCnt;
51 }
52 
53 
54 
55 int main()
56 {
57     char * str1 = "hello world.1...2";
58     char * str2 = "hello world.sd,fg!@!$!$!!!!!!!!!!!!hj.";
59     char * str3 = "hello world.fdfg)(*&&&*(hjdfh?>><>,...";
60     char * str4 = ".hello world.12";
61     int i = 0;
62     i = get_string_word_cnt(str1);
63     printf(" %d
",i);
64     i = get_string_word_cnt(str2);
65     printf(" %d
",i);
66     i = get_string_word_cnt(str3);
67     printf(" %d
",i);
68     i = get_string_word_cnt(str4);
69     printf(" %d
",i);
70 
71     return 0;
72 }
73 
74 /**
75     显示结果如下：
76 [ ][.][.][.][.]4
77 [ ][.][,][!][@][!][$][!][$][!][!][!][!][!][!][!][!][!][!][!][!][.]5
78 [ ][.][)][(][*][&][&][&][*][(][?][>][>][<][>][,][.][.][.]4
79 [.][ ][.]3
80 Press any key to continue
81 **/