数据结构练习(30)把数组排成最小的数

http://zhedahht.blog.163.com/blog/static/25411174200952174133707/

思路:

首先想到的应该是要把数字排序,经过简单的分析即可以得出如何自己定制compare函数。

作者博客里面的compare力求精简而忽略了效率,如果自己写的话应该能快不少。

#include <cstdio>
#include <cstring>
#include <cstdlib>

const int MAXN = 10;

int mycompare(const void* s1, const void* s2)
{
    char combine1[MAXN+1], combine2[MAXN+1];

    strcpy(combine1, *(const char**)s1);
    strcat(combine1, *(const char**)s2);

    strcpy(combine2, *(const char**)s2);
    strcat(combine2, *(const char**)s1);

    return strcmp(combine1, combine2);
}

void PrintMinNumber(int n[], int len)
{
    if (n == nullptr || len <= 0)
        return ;

    char** szn = (char**)(new int[len]);
    for (int i = 0; i < len; ++i)
    {
        szn[i] = new char[MAXN];
        sprintf(szn[i], "%d", n[i]);
    }
    qsort(szn, len, sizeof(char*), mycompare);

    for (int i = 0; i < len; ++i)
        printf("%s", szn[i]);
    printf("\n");

    for (int i = 0; i < len; ++i)
        delete[] szn[i];
    delete[] szn;
}

int main()
{
    int n[10] = {32, 321};
    PrintMinNumber(n, 2);
    return 0;
}
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kedebug

Department of Computer Science and Engineering,

Shanghai Jiao Tong University

E-mail: kedebug0@gmail.com

GitHub: http://github.com/kedebug

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原文地址:https://www.cnblogs.com/kedebug/p/2822471.html