判断两条线段是否相交

模板(hdu1086)

include <iostream>

using namespace std;
struct point
{
    double x,y;
};
struct segment
{
    point begin,end;
};
double min(double x,double y)
{
    return x<y?x:y;
}
double max(double x,double y)
{
    return x>y?x:y;
}
bool onsegment(point pi,point pj,point pk) //判断点pk是否在线段pi pj上
{
    if(min(pi.x,pj.x)<=pk.x&&pk.x<=max(pi.x,pj.x))
    {
        if(min(pi.y,pj.y)<=pk.y&&pk.y<=max(pi.y,pj.y))
        {
            return true;
        }
    }
    return false;
}
double direction(point pi,point pj,point pk) //计算向量pkpi和向量pjpi的叉积
{
    return (pi.x-pk.x)*(pi.y-pj.y)-(pi.y-pk.y)*(pi.x-pj.x);
}
bool judge(point p1,point p2,point p3,point p4) //判断线段p1p2和p3p4是否相交
{
    double d1 = direction(p3,p4,p1);
    double d2 = direction(p3,p4,p2);
    double d3 = direction(p1,p2,p3);
    double d4 = direction(p1,p2,p4);
    if(d1*d2<0&&d3*d4<0)
        return true;
    if(d1==0&&onsegment(p3,p4,p1))
        return true;
    if(d2==0&&onsegment(p3,p4,p2))
        return true;
    if(d3==0&&onsegment(p1,p2,p3))
        return true;
    if(d4==0&&onsegment(p1,p2,p4))
        return true;
    return false;
}
int main()
{
    int n,count;
    segment seg[101];
    while(cin>>n&&n)
    {
        count = 0;
        for(int i=1; i<=n; i++)
        {
            cin>>seg[i].begin.x>>seg[i].begin.y>>seg[i].end.x>>seg[i].end.y;
        }
        for(int i=1; i<n; i++)
            for(int j=i+1; j<=n; j++)
            {
                if(judge(seg[i].begin,seg[i].end,seg[j].begin,seg[j].end))
                {
                    count++;
                }
            }
            cout<<count<<endl;
    }
    return 0;
}
原文地址:https://www.cnblogs.com/keanuyaoo/p/3266731.html