如何处理webView跳转

- (void)webView:(UIWebView *)wv didFailLoadWithError:(NSError *)error {
    // Give iOS a chance to open it.
    NSURL *url = [NSURL URLWithString:[error.userInfo objectForKey:@"NSErrorFailingURLStringKey"]];
    if ([error.domain isEqual:@"WebKitErrorDomain"]
        && error.code == 101
        && [[UIApplication sharedApplication]canOpenURL:url])
    {
        [[UIApplication sharedApplication]openURL:url];
        return;
    }

    // Normal error handling…
}
 
- (BOOL)webView:(UIWebView *)wv shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {

    // Determine if we want the system to handle it.
    NSURL *url = request.URL;
    if (![url.scheme isEqual:@"http"] && ![url.scheme isEqual:@"https"]) {
        if ([[UIApplication sharedApplication]canOpenURL:url]) {
            [[UIApplication sharedApplication]openURL:url];
            return NO;
        }
    }
    return YES;
}
 
- (void)webView:(UIWebView *)wv didFailLoadWithError:(NSError *)error {
    // Ignore NSURLErrorDomain error -999.
    if (error.code == NSURLErrorCancelled) return;

    // Ignore "Fame Load Interrupted" errors. Seen after app store links.
    if (error.code == 102 && [error.domain isEqual:@"WebKitErrorDomain"]) return;

    // Normal error handling…
}
 
转自:http://stackoverflow.com/questions/4299403/how-to-handle-app-urls-in-a-uiwebview
原文地址:https://www.cnblogs.com/jyking/p/5253048.html