在一串日期中合并连续的日期

输入：'2016-02-01','2016-02-02','2016-02-03','2016-02-04','2016-02-05','2016-02-06','2016-02-07','2016-02-08','2016-02-09','2016-02-10','2016-02-11','2016-02-13','2016-02-14','2016-02-16'

输出：2016-02-01到2016-02-11,2016-02-13到2016-02-14,2016-02-16

代码：

 1 <?php
 2 $a = ['2016-02-01','2016-02-02','2016-02-03','2016-02-04','2016-02-05','2016-02-06','2016-02-07','2016-02-08','2016-02-09','2016-02-10','2016-02-11','2016-02-13','2016-02-14','2016-02-16'];
 3 $c = array();
 4 $length = count($a);
 5 $today = new DateTime();
 6 $oneDayInterval = new DateInterval('P1D');
 7 $temp[] = $a[0];
 8 for($i=0;$i<$length;$i++){
 9     if(DateTime::createFromFormat('Y-m-d',$a[$i])->add($oneDayInterval) == DateTime::createFromFormat('Y-m-d',$a[$i+1])){
10         $temp[] = $a[$i+1];
11     }else{
12         $c[] = $temp;
13         $temp = [];
14         $temp[] = $a[$i+1];
15     }
16 }
17 foreach($c as &$value){
18     if(count($value) > 1){
19         $value = current($value).'到'.end($value);
20     }else{
21         $value = implode(',',$value);
22     }
23 }
24 unset($value);
25 $d = implode(',',$c);
26 var_dump($d);