Add Digits



Given num = 38, the process is like: 3 + 8 = 111 + 1 = 2. Since 2 has only one digit, return it

{ public: int addDigits(int num) { return 1 + (num - 1) % 9; } };
1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,……
原文地址:https://www.cnblogs.com/julie-yang/p/6307724.html