LeetCode--SQL 查询:SQL实现分数排名

编写一个 SQL 查询来实现分数排名。

如果两个分数相同,则两个分数排名(Rank)相同。请注意,平分后的下一个名次应该是下一个连续的整数值。换句话说,名次之间不应该有“间隔”。

+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

例如,根据上述给定的 Scores 表,你的查询应该返回(按分数从高到低排列):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+
思路:按行(group by)循环获取比当前行分数大的不重复条数(count distinct),即该行分数的排名
SELECT
    s1.Score,
    count( DISTINCT ( s2.score ) ) Rank 
FROM
    Scores s1,
    Scores s2 
WHERE
    s1.score <= s2.score 
GROUP BY
    s1.Id 
ORDER BY
    Rank 
 
慢慢来才是最快的
原文地址:https://www.cnblogs.com/jongty/p/12618419.html