得到常用汉字的拼音首字母

这是网上的一段源码，能够将一个汉语字符串转换成拼音的首字母。

 1 #include   <iostream>   
 2 #include   <string>   
 3   using   namespace   std;   
 4     
 5   static   char   convert(wchar_t   n);   
 6   static   bool   In(wchar_t   start,   wchar_t   end,   wchar_t   code);   
 7     
 8   int   main(int   argc,   char*   argv[])   
 9   {   
10   string   sChinese   =   "我爱中国";   //   输入的字符串   
11     
12   char   chr[3];   
13   wchar_t   wchr   =   0;   
14     
15   char*   buff   =   new   char[sChinese.length()/2];   
16   memset(buff,   0x00,   sizeof(char)*sChinese.length()/2+1);   
17     
18   for   (int   i   =   0,   j   =   0;   i   <   (sChinese.length()/2);   ++i)     
19   {   
20   memset(chr,   0x00,   sizeof(chr));   
21   chr[0]   =   sChinese[j++];   
22   chr[1]   =   sChinese[j++];   
23   chr[2]   =   '/0';   
24     
25   //   单个字符的编码   如：'我'   =   0xced2   
26   wchr   =   0;   
27   wchr   =   (chr[0]   &   0xff)   <<   8;   
28   wchr   |=   (chr[1]   &   0xff);   
29     
30   buff[i]   =   convert(wchr);   
31   }   
32     
33   cout   <<   "pin   yin   =   ["   <<   buff   <<   "]"   <<   endl;   
34   system("pause"); 
35   return   0;   
36   }   
37     
38   char   convert(wchar_t   n)   
39   {   
40   if   (In(0xB0A1,0xB0C4,n))   return   'a';   
41   if   (In(0XB0C5,0XB2C0,n))   return   'b';   
42   if   (In(0xB2C1,0xB4ED,n))   return   'c';   
43   if   (In(0xB4EE,0xB6E9,n))   return   'd';   
44   if   (In(0xB6EA,0xB7A1,n))   return   'e';   
45   if   (In(0xB7A2,0xB8c0,n))   return   'f';   
46   if   (In(0xB8C1,0xB9FD,n))   return   'g';   
47   if   (In(0xB9FE,0xBBF6,n))   return   'h';   
48   if   (In(0xBBF7,0xBFA5,n))   return   'j';   
49   if   (In(0xBFA6,0xC0AB,n))   return   'k';   
50   if   (In(0xC0AC,0xC2E7,n))   return   'l';   
51   if   (In(0xC2E8,0xC4C2,n))   return   'm';   
52   if   (In(0xC4C3,0xC5B5,n))   return   'n';   
53   if   (In(0xC5B6,0xC5BD,n))   return   'o';   
54   if   (In(0xC5BE,0xC6D9,n))   return   'p';   
55   if   (In(0xC6DA,0xC8BA,n))   return   'q';   
56   if   (In(0xC8BB,0xC8F5,n))   return   'r';   
57   if   (In(0xC8F6,0xCBF0,n))   return   's';   
58   if   (In(0xCBFA,0xCDD9,n))   return   't';   
59   if   (In(0xCDDA,0xCEF3,n))   return   'w';   
60   if   (In(0xCEF4,0xD188,n))   return   'x';   
61   if   (In(0xD1B9,0xD4D0,n))   return   'y';   
62   if   (In(0xD4D1,0xD7F9,n))   return   'z';   
63   return   '/0';   
64   }   
65     
66   bool   In(wchar_t   start,   wchar_t   end,   wchar_t   code)   
67   {   
68   if   (code   >=   start   &&   code   <=   end)     
69   {   
70   return   true;   
71   }   
72   return   false;   
73   }

但是这种方法不能解决汉语和英语字符混合出现的情况，只需要加一个简单的判断即可。

判断当前字符的ASCII码范围是否符合英语的标准。

实现方法如下

string CPasswordDlg::getShortName(string name)
  {
      string shortName;
      for(int j = 0; j < name.length(); j++)
        {
            char m = name[j];
            if(name[j] > 47 && name[j] < 123)
            {
                shortName +=  name[j];
            }
            else
            {
                char   chr[3];   
                wchar_t   wchr   =   0;   

                memset(chr,   0x00,   sizeof(chr));   
                chr[0]   =   name[j++];   
                chr[1]   =   name[j];   
                chr[2]   =   '/0';   

                
                wchr   =   0;   
                wchr   =   (chr[0]   &   0xff)   <<   8;   
                wchr   |=   (chr[1]   &   0xff);   

                shortName += convert(wchr);

            }
        }
      return shortName;
  }

 1 char   CPasswordDlg::convert(wchar_t   n)   
 2   {   
 3   if   (In(0xB0A1,0xB0C4,n))   return   'a';   
 4   if   (In(0XB0C5,0XB2C0,n))   return   'b';   
 5   if   (In(0xB2C1,0xB4ED,n))   return   'c';   
 6   if   (In(0xB4EE,0xB6E9,n))   return   'd';   
 7   if   (In(0xB6EA,0xB7A1,n))   return   'e';   
 8   if   (In(0xB7A2,0xB8c0,n))   return   'f';   
 9   if   (In(0xB8C1,0xB9FD,n))   return   'g';   
10   if   (In(0xB9FE,0xBBF6,n))   return   'h';   
11   if   (In(0xBBF7,0xBFA5,n))   return   'j';   
12   if   (In(0xBFA6,0xC0AB,n))   return   'k';   
13   if   (In(0xC0AC,0xC2E7,n))   return   'l';   
14   if   (In(0xC2E8,0xC4C2,n))   return   'm';   
15   if   (In(0xC4C3,0xC5B5,n))   return   'n';   
16   if   (In(0xC5B6,0xC5BD,n))   return   'o';   
17   if   (In(0xC5BE,0xC6D9,n))   return   'p';   
18   if   (In(0xC6DA,0xC8BA,n))   return   'q';   
19   if   (In(0xC8BB,0xC8F5,n))   return   'r';   
20   if   (In(0xC8F6,0xCBF0,n))   return   's';   
21   if   (In(0xCBFA,0xCDD9,n))   return   't';   
22   if   (In(0xCDDA,0xCEF3,n))   return   'w';   
23   if   (In(0xCEF4,0xD188,n))   return   'x';   
24   if   (In(0xD1B9,0xD4D0,n))   return   'y';   
25   if   (In(0xD4D1,0xD7F9,n))   return   'z';   
26   return   '/0';   
27   }

1   bool   CPasswordDlg::In(wchar_t   start,   wchar_t   end,   wchar_t   code)   
2   {   
3   if   (code   >=   start   &&   code   <=   end)     
4   {   
5   return   true;   
6   }   
7   return   false;   
8   }