快速排序和快速选择(quickSort and quickSelect)算法

排序算法:快速排序(quicksort)递归与非递归算法
TopK问题:快速选择(quickSelect)算法

import java.util.*;
import java.lang.*;


public class Demo {

	// 非递归 using stack
	public static void quickSortStack(int[] nums, int left, int right) {
		if (left >= right) return;

		Stack<Range> stack = new Stack<Range>();
		stack.push( new Range(left, right) );

		while( !stack.empty() ) {
			Range curRange = stack.pop();
			if (curRange.left < curRange.right) {
				int pivotIdx = partition(nums, curRange.left, curRange.right);
				stack.push( new Range(curRange.left, pivotIdx - 1) );
				stack.push( new Range(pivotIdx + 1, curRange.right) );
			}
		}
	}

	// recursion quickSort
	public static void quickSort(int[] nums, int left, int right) {
			if (left < right) {
					int pIdx = partition(nums, left, right);
					quickSort(nums, left, pIdx - 1);
					quickSort(nums, pIdx + 1, right);
			} 
	}

	public static int partition(int[] nums, int left, int right) {
		// nums[left]~nums[retIdx - 1] <= nums[retIdx] <= nums[retIdx ~ right]
		if (left == right) return left;

		int pivot = nums[left]; // mark the leftmost value as the pivot. and store it.
		int lp = left, rp = right;
		while(lp < rp) {
			while(lp < rp && nums[rp] >= pivot)
				rp--;
			nums[lp] = nums[rp]; //move the smaller value to left Range.

			while(lp < rp && nums[lp] <= pivot)
				lp++;
			nums[rp] = nums[lp]; // move the bigger value to right Range.
		}
		nums[lp] = pivot;

		return lp;
	}

	public static void swap(int[] nums, int i, int j) {
			int tmp = nums[i];
			nums[i] = nums[j];
			nums[j] = tmp;
	}

	public static int partitionV2(int[] nums, int left, int right) {
		int l = left;
		int r = right + 1;
		int pivot = nums[left];
		while(true) {
			while( l < right && nums[++l] < pivot )
				if ( l == right ) break;
			while( r > left && nums[--r] >= pivot )
				if ( r == left ) break;

			if (l >= r)
				break;
			swap(nums, l, r);
		}
		swap(nums, left, r);
		return r;
	}

	//TopK问题
	public static int findKthLargest(int[] nums, int k) {
			return quickSelect(nums, k, 0, nums.length - 1);
	}

	//快速选择算法
	public static int quickSelect(int[] nums, int k, int left, int right) {
			if (left == right) return nums[left];
			int index = partition(nums, left, right);
			if ( index - left + 1 == k) {
					return nums[index];
			}
			else if ( index - left + 1 > k ) {
					return quickSelect(nums, k, left, index - 1);
			}
			else {
					return quickSelect(nums, k - index + left - 1, index + 1, right);
			}
	}

	public static void showArrays(int[] nums, String str) {
		System.out.println("===" + str + "===");
		showArrays(nums);
	}
	public static void showArrays(int[] nums) {
		for (int i = 0; i < nums.length; i++)
			System.out.printf(nums[i] + " ");
		System.out.println();
	}
	public static void main(String[] args) {
		int[] nums = new int[] {1,3,2,3,4,2,7,5};
		// int[] nums = new int[]{3,2,3};
		showArrays(nums, "origin");
		//print i-th min nubmer.
		for (int i = 1; i <= nums.length; i++) {
			System.out.println( i + " " + findKthLargest(nums, i) );
		}
		quickSortStack(nums, 0, nums.length - 1);
		showArrays(nums, "quickSortStack");
	}
}

class Range {
	public int left;
	public int right;

	public Range(int left, int right) {
		this.left = left;
		this.right = right;
	}
}
原文地址:https://www.cnblogs.com/johnleo/p/quicksort_and_quickselect.html