0924,函数返回多个值

    class Program    

{                

//函数多个返回值        

//输入参数前加Out就变成输出参数        

public int jisuan(int a, int b, out int c)        

{            

c = a - b;            

return a + b;        

}

       

public int jiefangcheng(int a, int b, int c, out double x1, out double x2)        

{            

x1 = 0;            

x2 = 0;            

if (0 == b * b - 4 * a * c)            

{                

x1 = (-b) / (2 * a);                

x2 = x1;                

return 1;            

}            

else if (0 < b * b - 4 * a * c)            

{                

x1 = (-b + Math.Sqrt(b * b - 4.0 * a * c)) / (2.0 * a);                

x2 = (-b - Math.Sqrt(b * b - 4.0 * a * c)) / (2.0 * a);                

return 2;            

}            

else            

{                

return 0;            

}        

}

原文地址:https://www.cnblogs.com/jlhea/p/4940750.html