简单的分支与循环结构 2 第一题

#include<stdio.h>
int main(void)
{
    int i,n;
    double r,h,v;
    double cylinder(double r,double h);

    printf("Enter n:");
    scanf("%d",&n);

    for(i=1;i<=n;i++){
        printf("Enter r and h:");
        scanf("%lf%lf",&r,&h);
        
        if(r<=0||h<=0)
        {
            printf("输入错误,重新输入");
        }
        else{
            v=cylinder(r,h);
            printf("v=%.3f
",v);
        }
    }
    return 0;
}
    double cylinder(double r,double h)
    {
        double result;

        result=3.1415926*r*r*h;
        
        return result;
    }
原文地址:https://www.cnblogs.com/jlg0322/p/3373385.html