12.输入一个正整数,输出它所有的因子

#include<iostream>
using namespace std;
void YinZi(int n);

int main()
{
int n;
cout<<"please input an number : "<<endl;
cin>>n;
YinZi(n);
return 0;
}

void YinZi(int n)
{
for(int i=1;i<=n;i++)
{
if(n%i==0)
cout<<i<<" ";
}
}
原文地址:https://www.cnblogs.com/jixiaowu/p/3890533.html