A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 244116 Accepted Submission(s): 47080

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

1 2

112233445566778899 998877665544332211

Sample Output

Case 1: 1 + 2 = 3

Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

代码：

 1 import java.util.*;    
 2 import java.math.*;    
 3 import java.io.*;    
 4 public class  Main       
 5 {    
 6     public static void main( String[] args  )    
 7     {    
 8        Scanner cin=new Scanner(new BufferedInputStream (System.in)  );      
 9        BigInteger a,b,c;                     
10        int t,num=0;    
11        t=cin.nextInt();                    
12        while( t-->=1 )    
13        {    
14            num++;     
15            a=cin.nextBigInteger();                
16            b=cin.nextBigInteger();    
17            c=a.add(b);    
18            System.out.println("Case "+num+":");            
19            System.out.println(a + " + " + b + " = "+c);    
20            if(t!=0)System.out.println("");    
21        }    
22     }    
23 }

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