485. Max Consecutive Ones

题目：Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

个人解法：（python）

class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        count = 0
        arr_result = []
        for i in range(len(nums)):
            if nums[i] == 1:
                count += 1
            else:
                if count != 0:
                    arr_result.append(count)
                count = 0
            if i == (len(nums)-1) and nums[i] == 1:
                arr_result.append(count)
        result = 0
        for i in arr_result:
            if i > result:
                result = i
        return result

看了别人的解法，思路一样，python中有个比较大小的max函数，忘记用了。

应该是：

class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        cnt = 0
        ans = 0
        for num in nums:
            if num == 1:
                cnt += 1
                ans = max(ans, cnt)
            else:
                cnt = 0
        return ans

第一遍做，没太考虑最优解，第二遍刷题的时候在考虑。