import itertools lst = [112, 123, 98, 132, 120] list(itertools.permutations(lst,2)) # 输出: # [(112, 123), # (112, 98), # (112, 132), # (112, 120), # (123, 112), # (123, 98), # (123, 132), # (123, 120), # (98, 112), # (98, 123), # (98, 132), # (98, 120), # (132, 112), # (132, 123), # (132, 98), # (132, 120), # (120, 112), # (120, 123), # (120, 98), # (120, 132)] list(itertools.combinations(lst, 2)) # 输出: # [(112, 123), # (112, 98), # (112, 132), # (112, 120), # (123, 98), # (123, 132), # (123, 120), # (98, 132), # (98, 120), # (132, 120)]
利用python itertools对列表实现排列组合
作者:jsp
-------------------------------------------
个性签名:无论在哪里做什么,只要坚持服务、创新、创造价值,其它的东西自然都会来的。
如果觉得这篇文章对你有小小的帮助的话,记得在右下角点个“推荐”哦,博主在此感谢!